Bellows
TID Fluid Area:
It seems
reasonably apparent that in a system with a
bellows the pipe internal fluid pressure load is
not balanced y pipe longitudinal tensile forces
and must be restrained by externbal forces. It can
also be seen that if the bellows ID exceeds the
pipe ID, an additional pressure force will be
transmitted through the pipe as a compression load
which must also be externally restrained. Hence
one component of the total bellows thrust load is
based on the bellows ID. |
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Bellows
ID Area =  |
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Corrugation
Sidewall Thrust:
It
can also be visualized that internal pressure
acting on the sidewall of the corrugation would
tend to spread the corrugation out in the
longitudinal direction, and this load must be
restrained by an external reaction force. As an
approximation consider a 1" wide radial strip
cut out of a corrugation.
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For
a fixed ended beam with uniform load, RID =
ROD =
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one half of the corrugation sidewall load is
carried in tension at the crest of the
corrugation. The other half it transmitted through
the neck of the corrugation as a compressive
force. This force must be resisted by the external
main anchors and results in a (generally) small
longitudinal compressive stress in the pipe. |
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Sidewall
Effective Area =
But ID + h = mean dia. = Dm
Therefore, Sidewall Effective Area =
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Total Effective Thrust Area:
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Ae=ID
area + Sidewall area
Ae=
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| A
more precise development of corrugation sidewall
load and an equation for bellows effective thrust
area is given in the Appendix. A comparison on 5
sample problems of typical bellows dimensions,
including one extreme case of OD/ID ratio, shows
that the percent error involved in using the mean
diameter approximation is generally less than 1%
and only 1 1/2% in the extreme example. |
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